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1 قطعة تيار مستمر 5 فولت WCS1800 قاعة جهاز استكشاف الحالي وحدة 35A مع مصباح التيار الزائد

KWD 6

ماركة
Comimark
وزن
14 g
1 +

مميزات خاصة

  • WCS1800 hall current sensor mainly has two functions: one is followed analog signal via power amplifier, and it can be applied to A/D conversion; the other is on-off signal.
  • Users can preset the limit current value. When the actual current is higher than preset current, the on-off signal will become high level from low level, and there is LED indicator lamp. It is simple and easy to use.
  • Interface definition: VCC: power positive/DOUT: TTL high/low level signal output/GND: power negative/AOUT: sampling current signal conversion voltage output port
  • Package Includes : 1PCS Module (If the number of products received is incorrect, please contact us . we will refund or give you a replacement)
  • We highly appreciate all customers opinions to improve the selling, also if anything you unsatisfied, please contact us for probable best solution.

وصف

Operating Voltage: DC 5V
Current Detection Range: DC +/-35A; AC 25A (for analog output)
Linearity: K=60mV/A
Limit Current Range: 0.5A-35A (for on-off value output)
With overcurrent signal indicator lamp
Sampling current conversion analog voltage signal output, and it can connect ADC; TTL level signal output, and it can connect MCU IO port control
Output signal is analog voltage signal and on-off value signal
Board Size: 37*31mm
Analog Voltage Signal Output (AOUT) Using Introduction:
Relationship between detection current and analog signal output is shown as below:
Analog Signal Output: V0=Vcc*0.5la*K (Ia is actual current through current detection pin, and K is linearity )
For example input current is 1A , Vcc=5V, and WCS1800 linearity is 60mV/A.
Lets simply explain the corresponding relationship between WCS1800 detection current and output voltage:
1).When the current flows into from positive direction:
Formula: V0=Vcc*0.5+ Ia*K
Corresponding output: V0=(2.5+0.06)V=2.56V
2).When the current flows into from negative direction:
Formula: V0=Vcc*0.5- Ia*K
Corresponding output V0=(2.5-0.06)V=2.44V
.If it is AC signal:
V0=Vcc*0.5+ Ia*K
Corresponding output range: 2.44V-2.56V
Above are ideal values, and there might be some little precision error.

منتجات شبيهه


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